Sum

In figure, QA and PB are perpendicular to AB. If AO = 10 cm, BO = 6 cm and PB = 9 cm. Find AQ

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#### Solution

In triangles AOQ and BOP, we have

∠OAQ = ∠OBP [Each equal to 90º]

∠AOQ = ∠BOP [Vertically opposite angles]

Therefore, by AA-criterion of similarity

∆AOQ ~ ∆BOP

`\Rightarrow \frac{AO}{BO}=\frac{OQ}{OP}=\frac{AO}{BP}`

`\Rightarrow \frac{AO}{BO}=\frac{AQ}{BP}\Rightarrow\frac{10}{6}=\frac{AQ}{9}`

`\Rightarrow AQ=\frac{10\times 9}{6}=15\text{ }cm`

Concept: Similarity

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